How to display the value of hidden when checkbox is checked in PHP

Im having problem on how to get the value of the hidden input box once the checkbox is checked. here are my code.

<label class="control control--checkbox"><span>Additional</span>
   <input type="checkbox" name="apply[]" value=""/>
   <input type="hidden" name="option[]" value="1 bottle"/>
   <input type="hidden" name="cost[]" value="$20"/>
</label>
<label class="control control--checkbox"><span>Additional</span>
   <input type="checkbox" name="apply[]" value=""/>
   <input type="hidden" name="option[]" value="3 bottle"/>
   <input type="hidden" name="cost[]" value="$50"/>
</label>

My Php code:

<?php 
$options = $_POST['option'];
$costs = $_POST['cost']; 
$apply = $_POST['apply'];
if (isset($apply)) {
    foreach ($options as $option) {
    echo '<tr>';
    echo '<td>'.$option.'</td>';
    echo '</tr>';
    }
}
?>

It seems that the option of my php code is always two, i want only to display that was checked and dont display that are not.

can someone advise me on how can i solve this problem or any work around to get the same result?