I have a following piece of code
public void showAlert(final Context context) {
mContext = context;
AlertDialog.Builder builder = new AlertDialog.Builder(context);
LayoutInflater inflater = (LayoutInflater) context.getSystemService(
Context.LAYOUT_INFLATER_SERVICE );
View view = inflater.inflate(R.layout.alert_dialog_layout,null);
builder.setView(view);
final CheckBox checkBox = (CheckBox)view.findViewById(R.id.checkBox);
try {
checkBox.setOnCheckedChangeListener(
new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView,
boolean isChecked) {
if (isChecked) {
Log.d(getClass().getSimpleName(), "CheckBox is
CHecked");
} else {
Log.d(getClass().getSimpleName(), "CheckBox is
Not Checked");
}
Log.d(getClass().getSimpleName(), "Inside ChecBox
CheckedListner");
}
}
);
}
catch (Exception e){
Log.d("TAG","Exception-->"+e);
}
builder.setPositiveButton(PositiveButton, new
DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
//some code here:
}
});
builder.setNegativeButton(NegativeButton, new
DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
dialog.dismiss();
}
});
final AlertDialog alert = builder.create();
alert.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT);
alert.show();
}
Whenever someone press the CheckBox it closes the Alert Dialog, which i dont want. Actually when user click the checkbox i have some data which will be passed to a another listener(an Interface) but my dialog is getting closed when checkbox is clicked.
Can anybody tell me how to keep the alertdialog intact even if somebody click the checkbox.
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