I've this code done in c++ and I want to ask why when I press one CheckBox all of them change status. Example:
CB1 = Checked CB2 = UnChecked
CB1 = Press
CB1 = UnChecked CB2 = Checked
I want just to make work one of them, not the two at the same time.
Here you have the code:
LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
{
switch (msg)
{
case WM_CREATE:
{
//Load the background image
HWND hWndBackground;
HANDLE hBitmap;
hBitmap = LoadImage(NULL, TEXT("\header.bmp"), IMAGE_BITMAP, 0, 0, LR_LOADFROMFILE);
if (hBitmap != NULL)
{
hWndBackground = CreateWindow(TEXT("STATIC"), TEXT("image box"),
WS_CHILD | WS_VISIBLE | SS_BITMAP,
0, 0, 470, 130,
hwnd, (HMENU)2000, NULL, NULL);
SendMessage(hWndBackground, STM_SETIMAGE, IMAGE_BITMAP, LPARAM(hBitmap));
}
//Load CheckBox1
CreateWindow(TEXT("button"), TEXT("Show Title"),
WS_VISIBLE | WS_CHILD | BS_CHECKBOX,
25, 220, 114, 45,
hwnd, (HMENU)1, ((LPCREATESTRUCT)lParam)->hInstance, NULL);
CheckDlgButton(hwnd, 1, BST_CHECKED);
//Load Textbox1
CreateWindowEx(WS_EX_CLIENTEDGE, TEXT("Edit"), TEXT("140"),
WS_CHILD | WS_VISIBLE,
115, 230, 50, 25,
hwnd, NULL, NULL, NULL);
//Load Label1
CreateWindowW(L"Static", L"0",
WS_CHILD | WS_VISIBLE, 0, 0, 10, 30, hwnd, (HMENU)1, NULL, NULL);
//Load CheckBox2
CreateWindow(TEXT("button"), TEXT("Show Title1"),
WS_VISIBLE | WS_CHILD | BS_CHECKBOX,
25, 250, 114, 45,
hwnd, (HMENU)2, ((LPCREATESTRUCT)lParam)->hInstance, NULL);
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
break;
}
case WM_COMMAND:
{
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked) {
CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo");
}
else {
CheckDlgButton(hwnd, 1, BST_CHECKED);
//action("chatlim", 150, 0, 0);
}
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1) {
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
}
else {
CheckDlgButton(hwnd, 2, BST_CHECKED);
}
break;
}
case WM_DESTROY:
{
PostQuitMessage(0);
break;
}
}
return DefWindowProc(hwnd, msg, wParam, lParam);
}
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