I don't Know how to hide, and later show content when user click on button(checkbox). I made code but it doesn't work. When I click on checkbox, content won't hide. I want make when user clicks on checkbox that frist content hides and second shows. And if user clicks again on checkbox that frist content shows and second hides.
<script>
$(document).ready(function(){
$("#skin_rasa").click(function() {
if ($('#skin_rasa').css('display') == 'none')
{
$("#_hsync_skin_menu_id").hide("slow", function() {
$("#_hsync_skin_menu_rasa").show("slow");
});
}
if ($('#skin_rasa').css('display') != 'none')
{
$("#_hsync_skin_menu_rasa").hide("slow", function() {
$("#_hsync_skin_menu_id").show("slow");
});
}
});
});
</script>
@EDIT: I saw where I did mistake. Now it Works but only on 1st click.
<script>
$(document).ready(function(){
$("#skin_rasa").click(function() {
if ($('#_hsync_skin_menu_id').css('display') != 'none')
{
$("#_hsync_skin_menu_id").hide("slow", function() {
$("#_hsync_skin_menu_rasa").show("slow");
});
}
if ($('#_hsync_skin_menu_id').css('display') == 'none')
{
$("#_hsync_skin_menu_rasa").hide("slow", function() {
$("#_hsync_skin_menu_id").show("slow");
});
}
});
});
</script>
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