I have this gridview where I need to populate more than 25 database tables. These table are lookup table and this gridview is for lookup table maintenance purpose.
Instead of putting specific columns in gridview I directly bind the dataTable to gridview.
This below method assigns the active columns value which is "y"/"n" to checkbox.
<asp:GridView ID="gvTables" runat="server" CssClass="Grid" Width="100%" AutoGenerateColumns="true" Font-Names="Arial"
BorderWidth="1" PagerSettings-Mode="Numeric" Font-Size="8.7pt" Font-Bold="false" AlternatingRowStyle-BackColor="#f4f4f4"
HeaderStyle-BackColor="LightGray" AllowPaging="True" ShowFooter="false" PageSize="12"
OnPageIndexChanging="gvTables_PageIndexChanging"
OnRowDataBound="gvTables_RowDataBound"
OnRowCreated="gvTables_RowCreated"
OnSelectedIndexChanged="gvTables_SelectedIndexChanged">
<PagerStyle CssClass="pgr" />
</asp:GridView>
code:
private void SetCheckBoxesInGV()
{
////add checkboxes in place of active
for (int i = 0; i < gvTables.Rows.Count; i++)
{
System.Web.UI.WebControls.CheckBox chk = new System.Web.UI.WebControls.CheckBox();
chk.ID = "chk";
chk.Checked = gvTables.Rows[i].Cells[gvTables.Rows[0].Cells.Count - 1].Text.Trim() == "y" ? true : false;
gvTables.Rows[i].Cells[gvTables.Rows[0].Cells.Count - 1].Controls.Add(chk);
gvTables.Rows[i].Cells[gvTables.Rows[0].Cells.Count - 1].ControlStyle.CssClass = "ItemCenter";
}
}
So the last column looks like this instead of y/n.
Now I want to get the checkbox values, I am using this and thought it will work but it doesn't. Gives null value and "Object reference not set to an instance of an object".
((CheckBox)gvTables.Rows[i].Cells[gvTables.Rows[0].Cells.Count - 1].FindControl("chk")).Checked
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