I am trying to achieve show already stored values as selected.
my question is i am trying to fetch multiple facilitites from mapping table that is os_hostel_facility but when i try to show that only first value is coming in console even that is not showing as selected how can i do that my code is at bottom:
Please suggest edit if question does not reach standards..!
This is my script:
success: function (response) {
$("#viewhostelfacility").val(response['facility']['id_facility']);
console.log(response['facility']['id_facility']);
here only first value is coming and i want to show the whole array as selected
This is my update form code
<ul id="hostel_facility" class="dropdown-menu dropdown-select">
<?php $facility = $conn->query("SELECT * FROM os_facilities ORDER BY id_facility ASC");
while ($facilityresult = $facility->fetch_assoc()) { ?>
<li><a><input type="checkbox" name="hostel_facility[]" id="viewhostelfacility" value="<?php echo $facilityresult['id_facility']; ?>" /><?php echo $facilityresult['facility_name']; ?></a></li>
<?php } ?>
</ul>
And this my controller page from where i am sending ersponse:
$facilitysearch= $conn->query("SELECT * From os_hostel_facility WHERE id_hostel='".$_POST['hostelId']."'") or die(mysql_error());
$viewfacility=$facilitysearch->fetch_assoc();
$response['facility'] = $viewfacility;
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