I could replace the key into value in a Word template using below function.
def replace_text_in_paragraph(paragraph, key, value):
if key in paragraph.text:
inline = paragraph.runs
# Replace strings and retain the same style.
# The text to be replaced can be split over several runs so
# search through, identify which runs need to have text replaced
# then replace the text in those identified
started = False
search_index = 0
# found_runs is a list of (inline index, index of match, length of match)
found_runs = list()
found_all = False
replace_done = False
for i in range(len(inline)):
# case 1: found in single run so short circuit the replace
if key in inline[i].text and not started:
found_runs.append((i, inline[i].text.find(key), len(key)))
text = inline[i].text.replace(key, str(value))
inline[i].text = text
replace_done = True
found_all = True
break
if key[search_index] not in inline[i].text and not started:
# keep looking ...
continue
# case 2: search for partial text, find first run
if key[search_index] in inline[i].text and inline[i].text[-1] in key and not started:
# check sequence
start_index = inline[i].text.find(key[search_index])
check_length = len(inline[i].text)
for text_index in range(start_index, check_length):
if inline[i].text[text_index] != key[search_index]:
# no match so must be false positive
break
if search_index == 0:
started = True
chars_found = check_length - start_index
search_index += chars_found
found_runs.append((i, start_index, chars_found))
if search_index != len(key):
continue
else:
# found all chars in key
found_all = True
break
# case 3: search for partial text, find subsequent run
if key[search_index] in inline[i].text and started and not found_all:
# check sequence
chars_found = 0
check_length = len(inline[i].text)
# print(check_length)
for text_index in range(0, check_length):
# print(key[search_index])
if inline[i].text[text_index] == key[search_index]:
search_index += 1
chars_found += 1
else:
break
# no match so must be end
found_runs.append((i, 0, chars_found))
if search_index == len(key):
found_all = True
break
if found_all and not replace_done:
for i, item in enumerate(found_runs):
index, start, length = [t for t in item]
if i == 0:
text = inline[index].text.replace(
inline[index].text[start:start + length], str(value))
inline[index].text = text
else:
text = inline[index].text.replace(
inline[index].text[start:start + length], '')
inline[index].text = text
But how could I change the checkbox value.
If Word could not, be open to suggest a fillable pdf as when you create a fillable checkbox in pdf it can be given a JavaScript ID to this checkbox. But I do not know how to achieve that. That is all I can come up with.
Any help will be appreciated.
Aucun commentaire:
Enregistrer un commentaire