How Do I Implement Checkbox Functionality in PySimpleGUIQt?

I'm trying to create a simple GUI program in Python that I'd use when creating new projects. I'd like a tickbox functionality for what type of project it is (python, web, etc) and then an input box for the project name (what the directory name would be).

import os
import PySimpleGUIQt as sg

sg.change_look_and_feel('DarkAmber') #colour

#layout of window
layout = [ 
    [sg.Text('File Types')],
    [sg.Text('1. Python file (start.py)')],
    [sg.Text('2. Web app (script.js, index.html, styles.css)')],
    [sg.Text('Choose your file type (1 or 2):'), sg.InputText()],
    [sg.Text('Project Name:'), sg.InputText()],
    [sg.Button('Ok'), sg.Button('Cancel')],
]
window = sg.Window('Project Creator', layout) #make the window

event, values = window.read()
ProjectName = values[1]

def make_file_python(ProjectName): #function to make python project
    os.makedirs('../' + ProjectName)
    open(f"..\{ProjectName}\start.py", 'x')
def make_file_webapp(ProjectName): #function to make webapp project
    os.makedirs('../' + ProjectName)
    open(f"..\{ProjectName}\index.html", 'x')
    open(f"..\{ProjectName}\style.css", 'x')
    open(f"..\{ProjectName}\script.js", 'x')

count = 0
while count < 1:
    if event in (None, 'Cancel'):
        break
    elif values[0] == '1':
        make_file_python(ProjectName)
        count +=1
    elif values[0] == '2':
        make_file_webapp(ProjectName)
        count +=1
    elif count >= 1:
        break

window.close()

I've made the functions so that if python is selected, the new folder will contain a "start.py" file, and if web is selected, the folder will contain "script.js, styles.css, index.html".

At the moment the only way I can choose whether the file type will be python or webapp is by inputting either '1' or '2' respectively. This is just a placeholder and a checkbox functionality would be much more practical, so I'm asking for help as to how to implement this in.