i have made a form in which user checks the check box..and after selecting it click on a OK button and its value goes on another page... I just want a checked after i hit the OK button..its type is submit though..I just want a simple solution in java script, j query or ajax but not in PHP .. Kindly please help me..Thanks for your help in advance... i have tried the php code but its giving errors and its making everything so complicated, i don't wanna do complicated...
<?php
include 'connection.php';
$sql="SELECT * FROM `tbl`";
$query=mysqli_query($connect,$sql);
echo "<table border='2px'>
<thead>
<th>ID</th>
<th>Title</th>
<th>Name</th>
<th>Doing</th>
<th>Done</th>
</thead>";
echo "<form method='POST'>";
echo "<tr>";
while($res=mysqli_fetch_assoc($query)){
$id=$res['id'];
echo" <td>{$res['id']}</td>
<td>{$res['title']}</td>
<td>{$res['name']}</td>
<td><input type='checkbox' name='doing[]'
value='".$res['id'].$res['title'].$res['name']."'></td>
<td><input type='checkbox' name='done[]'
value='".$res['id'].$res['title'].$res['name']."'></td>
</tr>"
;}
echo "</table>";
echo "<input type='submit' value='OK' name='btn'>";
echo "</form>";
?>
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